A four-bit binary number is represented as A 3 A 2 A 1 A 0, where

A four-bit binary number is represented as A₃A₂A₁A₀, where A₃, A₂, A_1, and A₀ represent the individual bits and A₀ is equal to the LSB.

The correct logical expression to get a HIGH output whenever the binary number is greater than 0010 and less than 1000 is;

A. \({\bar A_3}{A_2} + {\bar A_3}{A_1}{A_0} + {\bar A_3}{A_2}{A_1}\)

B. \({\bar A_3}{A_2} + {\bar A_3}{A_2}{A_1}\)

C. \({\bar A_3}{A_2}\)

D. \({\bar A_3}{A_2} + {\bar A_3}{A_1}{A_0}\)

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The Truth Table for the required operation is as shown:

Using K-map to simplify the expression, we get:

F = A̅₃A₂ + A̅₃A₁A₀