A hot object loses heat to its surroundings in the form of heat r

A hot object loses heat to its surroundings in the form of heat r
| A hot object loses heat to its surroundings in the form of heat radiation. The rate of loss of heat depends on the

A. Temperature of the object

B. Temperature of the surrounding

C. Temperature difference between the object and its surrounding

D. Average temperature of the object and its surrounding

Please scroll down to see the correct answer and solution guide.

Right Answer is: C

SOLUTION

Concept:

  • According to Newton’s law of cooling, the rate of loss of heat from a body is directly proportional to the difference in the temperature of the body and its surroundings.
  • i.e., the rate of cooling ∝ ΔT


\(\therefore \frac{{dQ}}{{dt}} = - k\left( {\Delta T} \right)\)

⇒ dQ/dt is the rate of heat transfer or heat loss per sec (J/s)

⇒ (T2 – T1) is the temperature difference

⇒ k is some constant

Explanation:

  • Now we know that rate of heat transfer will depend upon the temperature difference of object and surrounding
  • Hence only option c is correct
  • Option A and B are incorrect since because heat transfer not completely depends upon either only on objects or surrounding temperature.