A light bulb draws 300 mA when the voltage across it is 240 V. Th

A light bulb draws 300 mA when the voltage across it is 240 V. Th
| A light bulb draws 300 mA when the voltage across it is 240 V. The resistance of the light bulb is;

A. 400 Ω

B. 600 Ω

C. 800 Ω

D. 1000 Ω

Please scroll down to see the correct answer and solution guide.

Right Answer is: C

SOLUTION

V = I × R

\(R = \frac{V}{I} = \frac{{240}}{{300 \times {{10}^{ - 3}}}} = 800\;{\rm{\Omega }}\)

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