An aeration basin with a volume of 400 m 3 contains mixed liquor

SOLUTION

Concept:

The total microbial mass in the aeration system (M) is computed by multiplying the average concentration of solids in the mixed liquor of the aeration tank, called Mixed Liquor Suspended Solids with the volume of the tank (V).

∴ M = MLSS × V

Calculation:

The concentration of mixed liquor suspended solids,

MLSS = 1000 mg/l ⇒ \(\frac{{1000 \times {{10}^{ - 6}}}}{{{{10}^{ - 3}}}}\;kg/{m^3} = \;1\;kg/{m^3}\)

For a volume of 400 m³,

M = 1 × 400 = 400 kg