If charge is distributed over a (curved) line, each differential

| If charge is distributed over a (curved) line, each differential charge dQ along the line produces a differential electric field:

A. \(dE = \frac{{dQ}}{{4\pi \varepsilon {r^2}}}{\hat a_r}\)

B. \(dE = \frac{{dQ\;{r^2}}}{{4\pi \varepsilon }}{\hat a_r}\)

C. \(dE = \frac{{dQ}}{{{r^2}}}{\hat a_r}\)

D. \(dE = \frac{{dQ}}{{4\pi \varepsilon r}}{\hat a_r}\)

Please scroll down to see the correct answer and solution guide.

The electric field intensity (or electric field strength) ‘E’ is defined as the force (F) per unit charge (Q) when placed in the electric field.

\(E = \frac{F}{Q}\)

The electric field intensity ‘E’ is always in the direction of the force ‘F’ and is measured in Newton per coulomb or volts/meter.

The electric field intensity due to a point charge is given by

\(E = \frac{Q}{{4\pi {\varepsilon _o}{R^2}}}{a_R}\)

Where,

R = Distance between a point charge and given point.