If the lateral compressive strain in a material is 0.3 × 10–3 and
If the lateral compressive strain in a material is 0.3 × 10–3 and the Poisson ratio is 0.25, then longitudinal strain in the material is
A. 0.0012 (tensile)
B. 0.0012 (compressive)
C. 7.5 × 10–5 (compressive)
D. 7.5 × 10–5 (tensile)
Please scroll down to see the correct answer and solution guide.
Right Answer is: A
SOLUTION
Concept:
\(Poisson\;ratio = \frac{{ - lateral\;strain\left( {{\varepsilon _{la}}} \right)}}{{longitudinal\;strain\left( {{\varepsilon _{lo}}} \right)}}\)
Calculation:
(εla) = 0.3 × 10-3, μ = 0.25
\(\mu = \frac{{ - 0.3 \times {{10}^{ - 3}}}}{{{\varepsilon _{lo}}}}\) …[comp → +ve]
\({\varepsilon _{lo}} = - \frac{{0.3}}{{0.25}} \times {10^{ - 3}} = - 0.0012\)
As we have considered compression as +ve,
Here –ve sign indicates tensile strain.
So, εlo = 0.0012 (Tensile)