In the circuit shown below Zener voltage is V Z = 5 V and β = 100
| In the circuit shown below Zener voltage is VZ = 5 V and β = 100. The value of ICQ and VCEQ are
A. 12.47 mA, 4.3 V
B. 12.47 mA, 5.7 V
C. 10.43 A, 5.7 V
D. 10.43 A, 4.3 V
Please scroll down to see the correct answer and solution guide.
Right Answer is: B
SOLUTION
We obtained the operating point in following steps.
Step 1: We redraw the given circuit as
Step 2 : Applying KVL in collector-base-emitter, we determine the emitter current (IEQ) as
12 – 500(IC + IB) – VZ – VBE = 0
Step 3: So, the collector current is given by
Step 4: Since, emitter is connected to ground, i.e. VE = 0. So, we determine the collector to emitter voltage (VCEQ) as
VC = VE + VBE + VZ
= 0 + 0.7 + 5 = 5.7
Step 5: Thus, the collector to emitter voltage is
VCE = VC – VE = 5.7 – 0 = 5.7 V
