In the equation ax+by+c=0 if y=cx+db then x = d+ca+c −d

In the equation ax+by+c=0, if y= $\frac{(c x + d)}{b}$ then x =

$\frac{d + c}{a + c}$

$\frac{- d - c}{a + c}$

$\frac{a + c}{d + c}$

None of these

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Given ax+by+c=0,

Also given y= $\frac{(c x + d)}{b}$ , substitute this in ax+by+c=0

We get ax+ [b $\frac{(c x + d)}{b}$ ]+c=0

So ax+cx+d+c=0

(a+c)x=-d-c

Therefore x= $\frac{- d - c}{a + c}$