In the shown circuit, if I = 30 ∠ 45° mA then phasor voltage V S
| In the shown circuit, if I = 30∠45° mA then phasor voltage VS is
A. 6 ∠0° V
B. 17 ∠45° V
C. 12 ∠–45° V
D. 6 ∠45° V
Please scroll down to see the correct answer and solution guide.
Right Answer is: D
SOLUTION
R = 200 Ω
jωL = j (104) (0.04) = j400 Ω
VS = IZ = (30∠45° × 10–3) (200 + j400 – j400)
= 30∠45° × 10–3 ×200 = 6 ∠45° V
