Mohan purchased a house for Rs 30000 and its value is d

SOLUTION

Present value of the house (P) = Rs. 30000
Rate of depreciation $=25\%$ p.a.
Period (n) = 3 years
$\therefore$ Value of house after 3 years $=P{(1-\frac{R}{100})}^n$
$=Rs.30000{(1-\frac{25}{100})}^3=Rs.30000{\left(\frac{3}{4}\right)}^3$
$=Rs.30000\times \frac{3}{4}\times \frac{3}{4}\times \frac{3}{4}=Rs.12656.25$