Question 5Tina had 20 m 5 cm long cloth She cuts 4 m 50

SOLUTION

We know that 100 cm = 1 m

$\therefore 1cm=\frac{1}{100}m$

$20m5cm=20m+5cm=20m+1cm\times 5=20m+\frac{1}{100}m\times 5=20m+0.05m=20.05m$

$4m50cm=4m+50cm=4m+1cm\times 50=4m+\frac{1}{100}m\times 50=4m+0.50m=4.50m$

Total length of cloth = 20 m 5 cm       = 20.05 m

Length of cloth used = 4 m 50 cm     = 4.50 m

Remaining cloth = 20.05 m – 4.50 m

$\begin{array}{cccccccc}\text{Hundreds}& \text{Tens}& \text{Ones}& .& \text{Tenths}& \text{Hundredths}& \text{Thousandths}& \\ 0& 2& 0& .& 0& 5& 0& \\ 0& 0& 4& .& 5& 0& 0& \\ -& & & & & & & \\ 0& 1& 5& .& 5& 5& 0& =15.55\end{array}$

Remaining cloth = 15.55 m

Therefore, 15.55 m of cloth is left with Tina.