The 90° bend allowance according to IS 2502-1963 for 6 mm diamete
| The 90° bend allowance according to IS 2502-1963 for 6 mm diameter mild steel bar
A. 30 mm
B. 36 mm
C. 54 mm
D. 75 mm
Please scroll down to see the correct answer and solution guide.
Right Answer is: D
SOLUTION
Concept:
Bends and Hooks Forming End Anchorages ( As per IS 2502:1963 )
Here
k = 2 for Mild Steel
k = 3 for Medium Tensile Steel
k = 4 for Cold-worked Steel
As per IS 2502:1963, P-6, Table-II
H = Hook allowance taken as 9d, 11d, 13d, and 17d for k values 2, 3, 4 and 6 respectively and rounded off to the nearest 5 mm, but not less than 75 mm.
B = Bend allowance is taken as 5d, 5.5d, 6d, and 7d for k values 2, 3, 4 and 6 respectively and rounded off to the nearest 5 mm, but not less than 75 mm.
Calculation:
Here K value is 2, as the type of steel is mild steel.
Bend allowance = 5 x 6 = 30 mm
But it is less than 75 mm. So provide 75 mm bend allowance.