The angle of elevation of a tower 120 m away is 30°. Find its hei
| The angle of elevation of a tower 120 m away is 30°. Find its height?
A. 80 √3 m
B. 60 m
C. 40 √3 m
D. 240 m
Please scroll down to see the correct answer and solution guide.
Right Answer is: C
SOLUTION
Analysis:
\(tan~\theta =\frac{Perpendicular}{Base}\)
From the figure:
\(tan30^\circ \; = \frac{{height\;of\;tower}}{{distance}}\)
\(\frac{1}{{\sqrt 3 }} = \frac{{height\;of\;tower}}{{120}}\)
\(Height=\frac{120}{\sqrt 3}\)
Height = 40√3 m
