The half-power beamwidth of 2m parabolic reflector used at 5 GHz

SOLUTION

Concept:

The half-power beamwidth of the parabolic reflector is given as:

\(HPBW = \frac{{70\;\lambda ^\circ }}{D}\)

Where,

λ = Wavelength

D = distance

Analysis:

Given:

f = 5 GHz, D = 2 m

We know that,

\(c = f\lambda \)

\(\lambda = \frac{C}{f}\)

\(\lambda = \frac{{3 \times {{10}^8}}}{{5 \times {{10}^9}}}\)

λ =.06 m

\(HPBW = \frac{{70\lambda ^\circ }}{D} = \frac{{70 \times .06}}{2}\)