The signal x(t) = e -6t u(t) is a
![The signal x(t) = e -6t u(t) is a](/img/relate-questions.png)
| The signal x(t) = e-6t u(t) is a
A. Power signal with P<sub>∞</sub> = 0
B. Power signal with P<sub>∞</sub> = 1/6
C. Energy signal with E<sub>∞</sub> = 0
D. Energy signal with E<sub>∞</sub> = 1/12
Please scroll down to see the correct answer and solution guide.
Right Answer is: D
SOLUTION
For the given signal
\(\begin{array}{l} {E_\infty } = \mathop \smallint \limits_{ - \infty }^\infty |x\left( t \right){|^2}dt\\ = \mathop \smallint \limits_{ - \infty }^\infty {e^{ - 12t}}u\left( t \right)dt\\ = \mathop \smallint \limits_0^\infty {e^{ - 12t}}dt\\ = \frac{1}{{12}} \end{array}\)