The simultaneous equations are given as follows: 2x + ay + z = 2

The simultaneous equations are given as follows:

2x + ay + z = 2
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The simultaneous equations are given as follows:

2x + ay + z = 20 

x + 3y + 4z = b

x + 2y + 3z = c

If the above equation has unique solution then which of the following is/are correct about the value of a, b and c?

A. a ≠ -1

B. a ≠ ± 1

C. b can take any value

D. c can take any value except 1

Please scroll down to see the correct answer and solution guide.

Right Answer is:

SOLUTION

Concept:

Consider the system of m linear equations

a11 x1 + a12 x2 + … + a1n xn = b1

a21 x1 + a22 x2 + … + a2n xn = b2

am1 x1 + am2 x2 + … + amn xn = bm

The above equations containing the n unknowns x1, x2, …, xn. To determine whether the above system of equations is consistent or not, we need to find the rank of the following matrices.

\(A = \left[ {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}}& \ldots &{{a_{1n}}}\\ {{a_{21}}}&{{a_{22}}}& \ldots &{{a_{2n}}}\\ \ldots & \ldots & \ldots & \ldots \\ {{a_{m1}}}&{{a_{m2}}}& \ldots &{{a_{mn}}} \end{array}} \right]\)

\(\left[ {A{\rm{|}}B} \right] = \left[ {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}}& \ldots &{{a_{1n}}}&{{b_1}}\\ {{a_{21}}}&{{a_{22}}}& \ldots &{{a_{2n}}}&{{b_2}}\\ \ldots & \ldots & \ldots & \ldots & \ldots \\ {{a_{m1}}}&{{a_{m2}}}& \ldots &{{a_{mn}}}&{{b_m}} \end{array}} \right]\)

A is the coefficient matrix and [A|B] is called an augmented matrix of the given system of equations.

We can find the consistency of the given system of equations as follows:

(i) If the rank of matrix A is equal to the rank of an augmented matrix and it is equal to the number of unknowns, then the system is consistent and there is a unique solution.

The rank of A = Rank of augmented matrix = n

(ii) If the rank of matrix A is equal to the rank of an augmented matrix and it is less than the number of unknowns, then the system is consistent and there are an infinite number of solutions.

The rank of A = Rank of augmented matrix < n

(iii) If the rank of matrix A is not equal to the rank of the augmented matrix, then the system is inconsistent, and it has no solution.

The rank of A ≠ Rank of an augmented matrix. 

Analysis:

For a given system of equations to have a unique solution, the determinant of the coefficient matrix should be not equal to 0.

\(\left| {\begin{array}{*{20}{c}} 2&a&1\\ 1&3&4\\ 1&2&3 \end{array}} \right| \ne 0\)

2(9 - 8) - a(3 - 4) + (2 - 3) ≠ 0

2 + a - 1 ≠ 0

a ≠ 1

Since Δ of the coefficient matrix is not equal to 0 then b and c can take any value.

Note: If coefficient matrix’s Δ ≠ 0 then rank of coefficient matrix is always equal rank of augmented matrix so right-hand side of given equation can take any value