# Free Patterns 01 Practice Test - 5th Grade

Complete the pattern.

3140624, 3140724, 3140824, _________

A.

314824

B.

3140124

C.

3140924

D.

3014864

#### SOLUTION

Solution : C

The pattern given is 3140624, 3140724, 3140824, _______

Let us calculate the difference between two consecutive terms.

3140724 - 3140624 = 100

3140824 - 3140724 = 100

We observe that each term in the sequence is 100 more than the previous term.

So, the next term in the sequence = 3140824 + 100 = 3140924

Which figure comes next? A. B. C. D.

None of these

#### SOLUTION

Solution : C

As we can observe in the above pattern, the four dots are rotated in clockwise direction in each step.

So the figure that comes next in the pattern will be: Find the next term
2123 , 3234, 4345, 5456, _____

A. 6467
B. 6567
C. 6556
D. 6565

#### SOLUTION

Solution : B

The given sequence is 2123 , 3234, 4345, 5456, _____.

We split the above sequence into four.
The sequence of the digits in the thousands place is 2, 3, 4, 5. Hence, the next term should be 6.

The sequence of the digits in the hundreds place is 1, 2, 3, 4. Hence, the next term should be 5.

The sequence of digits in the tens place is 2, 3, 4, 5. Hence, the next term should be 6.

The sequence of digits in the units place is 3, 4, 5, 6. So, the next number should be 7.

Considering all conditions, the next term of the sequence is 6567.

Find the next two terms.

1, 4,9, 16, 25, 36, ______ , ______

A.

47, 58

B.

49, 64

C.

44 , 57

D.

43 , 78

#### SOLUTION

Solution : B

The terms in the sequence are:

1=1×14=2×29=3×316=4×425=5×536=6×6

We observe that the nth term in the sequence is n × n.

So, the 7th term of the sequence = 7 × 7 = 49

The 8th term in the sequence = 8 × 8 = 64

So, the next two terms in the sequence are 49, 64.

If  6+4=210

8+5=313

10+6=416

then 15+3=______ ?

A.

520

B.

1218

C.

1219

D.

518

#### SOLUTION

Solution : B If ABCD = ZYXW, then CAB =______?

A.

XZY

B.

XYZ

C.

YXZ

D.

ZXY

#### SOLUTION

Solution : A

In the given pattern A = Z ; B = Y ; C = X ; D = W

CAB = XZY

In a certain code language

I am good134Life is good524

Then good is represented as _____.

A.

3

B.

4

C.

1

D.

5

#### SOLUTION

Solution : B

Iamgood134Lifeisgood524

In both the sentences good is represented as 4.

Hence  good =   4

A26  B25  C24  D23  E22  F21  G20  H19  I18  J17  K16  L15  M14  N13  O12  P11  Q10  R9  S8  T7  U6  V5  W4  X3  Y2  Z1

Note: Each alphabet is encoded to the number below it.
Using the given code, "G A L A X Y" can be encoded as ____.

A. 20 23 11 20 31
B.  20 25 15 25 4 1
C. 20 26 15 26 3 2
D. 25 26 23 10 9

#### SOLUTION

Solution : C

Here, each alphabet is represented with the number given below it.

G20, A26, L15, X3,  and Y2

GALAXY20 26 15 26 3 2

If A = '!', B = '^' ,C = '(', D =')' and T = '&'; then TAB = _____

A.

^()

B.

&!^

C.

^!&

D.

(^)

#### SOLUTION

Solution : B

Since T = &, A = !, B = ^

TAB = &!^

Complete the pattern. A. B. C. D. #### SOLUTION

Solution : D

In the pattern given above, each blue triangle has one more row of white triangles inside them than the previous one.

Also, the number of white triangles in the second row is one more than the number of triangles in the first row, if the blue triangle has white triangles inside it.

So, the next figure in the sequence will have 3 rows of white triangles and the first row will have 3 triangles.

So the figure that will come next in the pattern is : 