In the circuit shown in the figure, if ðķ = 0, the expression for

In the circuit shown in the figure, if ðķ = 0, the expression for
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In the circuit shown in the figure, if ðķ = 0, the expression for 𝑌 is

A. Y = A BĖ… + AĖ… B

B. Y = A + B

C. Y = AĖ… + BĖ… 

D. Y = A B

Please scroll down to see the correct answer and solution guide.

Right Answer is: A

SOLUTION

The given circuit is redrawn as:

The output will be:

\(Y = \overline {\left( {\overline {A + B} } \right) + AB} \)

\(Y = \overline {\bar A\bar B + AB} \)

\(Y = \overline {A \odot B} \)

Y = A B

Y = AĖ… B + A BĖ