In an isosceles triangle length of base is 20 cm and the altitude

In an isosceles triangle length of base is 20 cm and the altitude
| In an isosceles triangle length of base is 20 cm and the altitude of the triangle is 20% more than the base. Find the length of each equal side.

A. 40

B. 28

C. 30

D. 26

Please scroll down to see the correct answer and solution guide.

Right Answer is: D

SOLUTION

Base of isosceles triangle = 20 cm

⇒ Altitude AD = 20 × 120/100 = 24 cm

As we know,

⇒ D is 90° and divided BC in two equal part

⇒ (BA)2 = (BD)2 + (AD)2

⇒ (BA)2 = 102 + 242

⇒ BA = 26 cm